What Voltage Is Needed to Produce Electron Wavelengths of 0.36 Nm ?

joej

1. a 31-cm-diameter roll consists of 20 turns of copper wire 2.6mm in diameter. A uniform megnetic field perpendicular to the airplane of the coil, changes at a rate of 8.65 10 10 ^ -three T/southward
What is the electric current and what is the rate at which thermal energy is produced?

at present I figured this would be similar to emf induced in a moving conductor, thus that would give me the emf in volts and I could calculate the current using V = IR, however that dos not seem to give me the correct answer.
I am currently trying to figure out which forumula(s) to utilize to go an answer to this question.... however zero that I've tried and so far seems to work.

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ii. What voltage is needed to produce electron wavelength of .10nm? (assume electrons are nonrelativistic)

hither I tried to utilise the following two forumulas:

wavelength = Planck's constant / (mass * velocity)

and

eV = .5 mv^2

at present I used the 1st formula to to get v = ....

and inserted that into the second formula to get

eV = .5m ((wavelength * g) / (Planck's constant))^2

at present I convert from eV to Volts only.... respond is fashion off... where am I going incorrect here?

dextercioby

Post your numbers for the second problem.I'm sure u may take screwed upwardly the numbers...

Daniel.

P.S.As for the first problem,the conductor is non moving,equally,yes,u should apply Faraday's constabulary...

joej

okay well

h = 6.63 x 10 ^ -34 Js
or
four.xiv x 10 ^ -15 eVs

grand = nine.11 x 10 ^ -31

wavelength = 1 10 10 ^ -10 g

I become 2.2 x 10^ -82 eV I terminate here since this seems fashion off

dextercioby

Though i dislike the units for "h",i find that "lambda" is reasonable.Now tell me how did u get the energy that small??

Daniel.

joej

heh if I knew that I wouldn't be here :P

erm, just plugged it all into the forumla I posted earlier, I dunno why information technology turned out that small-scale.

equally for h, which is Planck's constant, being that small, I merely used what was given to us some fourth dimension ago as the accepted value for it.

should information technology exist unlike?

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Besides tried the 1st trouble using the equation:

EMF = (modify in flux)/(change in fourth dimension)

change in flux existence BA

then if we devide it by 1 second nosotros take B = eight.65 x 10 ^ -3 T
and surface area of cylinder is (2 * pi * r ^ 2) + (2 * pi * r * height) = 0.151 + 0.051 = 0.202m^2

BA = 1.75 x 10 ^ -3

BA / one = 1.75 x 10 ^ -3 5

at present... resistance of copper is 1.678 (micro-ohm-cm)

actually on 2d thought I think I already f*cked upward somewhere

Curious3141

For the 2nd part, I would suggest you attempt to work completely in symbols until the very final step.

Your answer is in electron-Volts, which is a unit of measurement of energy. The question is asking for the voltage. Fifty-fifty taking that into consideration, your reply is off.

Care for the electron every bit Newtonian (pregnant that all the "usual" equations for energy and momentum use).

Your awarding of De Broglie's equation is sound. And you're correct to attempt and find v from the kinetic energy. Utilise conservation of energy to equate qV (charge*voltage) to the kinetic energy 0.5*yard*5^two, and get an expression (in symbols) that relates the Voltage V to h, q (charge of electron), m (mass of electron) and the wavelength. Postal service the equation here.

You can only plug in the values in the equation and find the answer with less chance of error or confusion.

learningphysics

Also tried the 1st problem using the equation:
EMF = (modify in flux)/(alter in time)

modify in flux beingness BA

then if we devide it by 1 second nosotros have B = eight.65 ten 10 ^ -3 T
and surface expanse of cylinder is (2 * pi * r ^ two) + (2 * pi * r * elevation) = 0.151 + 0.051 = 0.202m^2

BA = 1.75 x ten ^ -3

BA / i = one.75 x 10 ^ -3 V

at present... resistance of copper is 1.678 (micro-ohm-cm)

actually on second thought I call up I already f*cked upwardly somewhere

The area you should be using is the cross exclusive area of the scroll. Just A=pi*r^2.

The flux through a single coil is BA. The flux through north coils is nBA. So, at present calculate EMF.

You should be able to calculate the total resistance of the coil, and then summate the current.

What Voltage Is Needed to Produce Electron Wavelengths of 0.36 Nm ?

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